Time and
Distance - General Questions
1.A person
crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
A.3.6
B.7.2
C.8.4
D.10
Answer:
Option-B
Explanation:
Speed = 600/
5 x 60 m/sec.
= 2 m/sec.
Converting
m/sec to km/hr (see important formulas section)
=2 x 18/5 km/hr
= 7.2 km/hr.
2.An
aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover
the same distance in 1 hours, it must travel at a speed of:
A.300 kmph
B.360 kmph
C.600 kmph
D.720 kmph
Answer:
Option-D
Explanation:
Distance =
(240 x 5) = 1200 km.
Speed =
Distance/Time
Speed =
1200/(5/3) km/hr. [We can write 1 2/3 hours AS 5/3 hours]
Required
speed =(1200 x 3/5)km/hr= 720 km/hr.
3.If a
person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more.
The actual distance travelled by him is:
A.50 km
B.56 km
C.70 km
D.80 km
Answer:
Option-A
Explanation:
Let the
actual distance travelled be x km.
Then, x/10 = x + 20 / 14
14x = 10x
+ 200
4x = 200
x = 50 km.
4.A train
can travel 50% faster than a car. Both start from point A at the same time and
reach point B 75 kms away from A at the same time. On the way, however, the
train lost about 12.5 minutes while stopping at the stations. The speed of the
car is:
A.100 kmph
B.110 kmph
C.120 kmph
D.130 kmph
Answer:
Option-C
Explanation:
Let speed
of the car be x kmph.
Then,
speed of the train = 150/100 X = 3/2x kmph.
75/X – 75/(3/2)X
= 12510X60
75/X – 50/X
= 5/24
X = (25x24
/5)
= 120 KMPH
5.Excluding
stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45
kmph. For how many minutes does the bus stop per hour?
A.9
B.10
C.12
D.20
Answer:
Option-B
Explanation:
Due to
stoppages, it covers 9 km less.
Time taken
to cover 9 km = (9/54 x 60) min = 10 min.
6.In a flight of 600 km, an aircraft was slowed
down due to bad weather. Its average speed for the trip was reduced by 200
km/hr and the time of flight increased by 30 minutes. The duration of the
flight is:
A.1 hour
B.2 hours
C.3 hours
D.4 hours
Answer: Option-
Explanation:
Let the duration of the flight be x hours.
Then, 600/X –
600/X+(1/2) =200
600/X – 1200/2X+1 =200
X(2X+1)
=3
2 X2 +X-3 =0
(2X + 3)(X-1) =0
X = 1 hr. [neglecting the -ve value of X ]
7.A man
complete a journey in 10 hours. He travels first half of the journey at the
rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total
journey in km.
A.220 km
B.224 km
C.230 km
D.234 km
Answer: Option-B
Expanation
(1/2)X/21
+ (1/2)X /24 =10
X/21 +X/24 =20
15X =168X20
X = {168/20 /15} =224KM.
8.The ratio between the speeds of two trains is 7 :
8. If the second train runs 400 km in 4 hours, then the speed of the first
train is:
A.70 km/hr
B.75 km/hr
C.84 km/hr
D.87.5 km/hr
Answer: Option-D
Explanation:Let the speed of two trains be 7x and
8x km/hr.
Then , 8X = [400/4] =100
X = [100/8] = 12.5
SOTHAT Speed of first train = (7x12.5) km/hr =87.5 km/hr.
9.A man
on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The
average speed for the first 320 km of the tour is:
A.35.55 km/hr
B.36 km/hr
C.71.11 km/hr
D.71
km/hr
Answer: Option- C
Explanation:
Total time taken =[160/64 +160/80]hrs.= 9/2hrs.
So Average speed = [320x2/9]km/hr.
=71.11km/hr.
10.A car
travelling with 5/7 of its
actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the
car.
A.17 6/7 km/hr
B.25 km/hr
C.30 km/hr
D.35
km/hr
Answer: Option-D
Explanation:
Time taken = 1 hr 40 min 48 sec. = 1 hr. 40 4/5 min
=1
Let the
actual speed be X km/hr.
Then , 5/7X x 126/75 = 42
X = [42x7x75 / 5x126]
=35 km/hr.
11.In covering a distance of 30 km, Abhay takes 2 hours more than
Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer.
Abhay's speed is:
A.5 kmph
B.6 kmph
C.6.25
kmph
D.7.5 kmph
Answer: Option-A
Explanation:
Let Abhay's speed be x km/hr.
Then, 30/x – 30/x =3
6x =30
X = 5km/hr.
12.Robert is travelling on his cycle and has calculated to reach point A
at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he
travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
A.8 kmph
B.11 kmph
C.12 kmph
D.14 kmph
Answer: Option-C
Explanation:
Let the distance travelled by x km.
THEN x/10 – x/15 = 2
3x -2x =60
X = 60 km.
Time taken to trevel 60 km at 10
km/hr. = [60/10] hrs.
So , Robert started 6 hours before 2 pm i.e. , at 8 am
So required speed = [60/5] kmph. = 12 kmph.
13.A farmer travelled a distance of 61 km in 9 hours. He travelled
partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance
travelled on foot is:
A.14 km
B.15 km
C.16 km
D.17 km
Answer: Option-c
Explanation:
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x)
km.
SO, x/4 + (61-x)/9 =9
9x +4(61-x) =9x36
5x =80
X=16km.