Analogy – Introduction

 

Analogy – Introduction

 Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

 

Introduction:

Analogy means similarity. In this type of questions, two objects related in some way are given and third object is also given with four or five alternatives. You have to find out which one of the alternatives bears the same relation with the third objects as first and second objects are related.

Example 1:

Curd : Milk :: Shoe : ?

(A) Leather      (B) Cloth

(C) Jute           (D) Silver

Answer: Option A

As curd is made from milk similarly shoe is made from leather.

 

Example 2:

Calf : Piglet :: Shed : ?

(A) Prison      (B) Nest

(C) Pigsty      (D) Den

Answer: Option C

Calf is young one of the cow and piglet is the young of Pig. Shed is the dwelling place of cow. Similarly Pigsty is the dwelling place of pig.

 

Example 3:

Malaria : Mosquito :: ? : ?

(A) Poison : Death      (B) Cholera : Water

(C) Rat : Plague          (D) Medicine : Disease

Answer: Option B

As malaria is caused due to mosquito similarly cholera is cause due to water.

 

Example 4:

ABC : ZYX :: CBA : ?

(A) XYZ      (B) BCA

(C) YZX      (D) ZXY

Answer: Option A

CBA is the reverse of ABC similarly XYZ is the reverse of ZYX.

Example 5:

4 : 18 :: 6 : ?

(A) 32      (B) 38

(C) 11      (D) 37

Answer: Option B

As, (4)² + 2 =18

Similarly, (6)² + 2 = 38.

 

LEADER OF THE HOUSE OF THE OPPOSITION

*■ LEADER OF THE HOUSE OF THE OPPOSITION*

*#Parliament*

◇ In each House of Parliament, there is the *‘Leader of the Opposition’.* The leader of the largest Opposition party having not less than one-tenth seats of the total strength of the House is recognised as the leader of the Opposition in that House.

◇ In a parliamentary system of government, the leader of the opposition has a significant role to play. His main functions are to provide a *constructive criticism* of the policies of the government and to provide an alternative government. Therefore, the leader of Opposition in the Lok Sabha and the *Rajya Sabha* were accorded statutory recognition in *1977.*

◇ They are also entitled to the salary, allowances and other facilities equivalent to that of a cabinet minister. 

◇ It was in *1969* that an official leader of the opposition was recognised for the first time. The same functionary in *USA is known as the ‘minority leader’.*

Important Indian Rulers

*◾Important Indian Rulers* 

 *➨ गुलाम वंश* 

1=1193 मुहम्मद  गौरी

2=1206 कुतुबुद्दीन ऐबक 

3=1210 आराम शाह

4=1211 इल्तुतमिश

5=1236 रुकनुद्दीन फिरोज शाह

6=1236 रज़िया सुल्तान

7=1240 मुईज़ुद्दीन बहराम शाह

8=1242 अल्लाउदीन मसूद शाह

9=1246 नासिरुद्दीन महमूद  

10=1266 गियासुदीन बल्बन

11=1286 कै खुशरो

12=1287 मुइज़ुदिन कैकुबाद

13=1290 शमुद्दीन कैमुर्स

1290 गुलाम वंश समाप्त्

(शासन काल-97 वर्ष लगभग )

 *➨ खिलजी वंश* 

1=1290 जलालुदद्दीन फ़िरोज़ खिलजी 

2=1296 

अल्लाउदीन खिलजी 

4=1316 सहाबुद्दीन उमर शाह

5=1316 कुतुबुद्दीन मुबारक शाह

6=1320 नासिरुदीन खुसरो  शाह

7=1320 खिलजी वंश स्माप्त

(शासन काल-30 वर्ष लगभग )

 *➨ तुगलक  वंश* 

1=1320 गयासुद्दीन तुगलक  प्रथम 

2=1325 मुहम्मद बिन तुगलक दूसरा   

3=1351 फ़िरोज़ शाह तुगलक 

4=1388 गयासुद्दीन तुगलक  दूसरा

5=1389 अबु बकर शाह

6=1389 मुहम्मद  तुगलक  तीसरा

7=1394 सिकंदर शाह पहला

8=1394 नासिरुदीन शाह दुसरा

9=1395 नसरत शाह

10=1399 नासिरुदीन महमद शाह दूसरा दुबारा सता पर

11=1413 दोलतशाह

1414 तुगलक  वंश समाप्त

(शासन काल-94वर्ष लगभग )

 *➨ सैय्यद  वंश* 

1=1414 खिज्र खान

2=1421 मुइज़ुदिन मुबारक शाह दूसरा

3=1434 मुहमद शाह चौथा

4=1445 अल्लाउदीन आलम शाह

1451 सईद वंश समाप्त

(शासन काल-37वर्ष लगभग )

 *➨ लोदी वंश* 

1=1451 बहलोल लोदी

2=1489 सिकंदर लोदी दूसरा

3=1517 इब्राहिम लोदी

1526 लोदी वंश समाप्त

(शासन काल-75 वर्ष लगभग )

 *➨ मुगल वंश* 

1=1526 ज़ाहिरुदीन बाबर

2=1530 हुमायूं 

1539 मुगल वंश मध्यांतर

 *➨ सूरी वंश* 

1=1539 शेर शाह सूरी

2=1545 इस्लाम शाह सूरी

3=1552 महमूद  शाह सूरी

4=1553 इब्राहिम सूरी

5=1554 फिरहुज़् शाह सूरी

6=1554 मुबारक खान सूरी

7=1555 सिकंदर सूरी

सूरी वंश समाप्त,(शासन काल-16 वर्ष लगभग )

 *➨ मुगल वंश पुनःप्रारंभ* 

1=1555 हुमायू दुबारा गाद्दी पर

2=1556 जलालुदीन अकबर

3=1605 जहांगीर सलीम

4=1628 शाहजहाँ

5=1659 औरंगज़ेब

6=1707 शाह आलम पहला

7=1712 जहादर शाह

8=1713 फारूखशियर

9=1719 रईफुदु राजत

10=1719 रईफुद दौला

11=1719 नेकुशीयार

12=1719 महमूद शाह

13=1748 अहमद शाह

14=1754 आलमगीर

15=1759 शाह आलम

16=1806 अकबर शाह

17=1837 बहादुर शाह जफर

1857 मुगल वंश समाप्त

(शासन काल-315 वर्ष लगभग )

 *➨ ब्रिटिश राज (वाइसरॉय)* 

1=1858 लॉर्ड केनिंग

2=1862 लॉर्ड जेम्स ब्रूस एल्गिन

3=1864 लॉर्ड जहॉन लोरेन्श

4=1869 लॉर्ड रिचार्ड मेयो

5=1872 लॉर्ड नोर्थबुक

6=1876 लॉर्ड एडवर्ड लुटेनलॉर्ड

7=1880 लॉर्ड ज्योर्ज रिपन

8=1884 लॉर्ड डफरिन

9=1888 लॉर्ड हन्नी लैंसडोन

10=1894 लॉर्ड विक्टर ब्रूस एल्गिन

11=1899 लॉर्ड ज्योर्ज कर्झन

12=1905 लॉर्ड गिल्बर्ट मिन्टो

13=1910 लॉर्ड चार्ल्स हार्डिंज

14=1916 लॉर्ड फ्रेडरिक सेल्मसफोर्ड

15=1921 लॉर्ड रुक्स आईजेक रिडींग

16=1926 लॉर्ड एडवर्ड इरविन

17=1931 लॉर्ड फ्रिमेन वेलिंग्दन

18=1936 लॉर्ड एलेक्जंद लिन्लिथगो

19=1943 लॉर्ड आर्किबाल्ड वेवेल

20=1947 लॉर्ड माउन्टबेटन

 *➨आजाद भारत,प्राइम मिनिस्टर* 

1=1947 जवाहरलाल नेहरू

2=1964 गुलजारीलाल नंदा

3=1964 लालबहादुर शास्त्री

4=1966 गुलजारीलाल नंदा

5=1966 इन्दिरा गांधी

6=1977 मोरारजी देसाई

7=1979 चरणसिंह

8=1980 इन्दिरा गांधी

9=1984 राजीव गांधी

10=1989 विश्वनाथ प्रतापसिंह

11=1990 चंद्रशेखर

12=1991 पी.वी.नरसिंह राव

13=अटल बिहारी वाजपेयी

14=1996 ऐच.डी.देवगौड़ा

15=1997 आई.के.गुजराल

16=1998 अटल बिहारी वाजपेयी

17=2004 डॉ.मनमोहनसिंह

18=2014 से  नरेन्द्र मोदी

Time and Distance - Data Sufficiency 1

 

Time and Distance - Data Sufficiency 1

Directions to Solve

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

·         Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.

·         Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.

·         Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.

·         Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.

·         Give answer(E) if the data in both Statements I and II together are necessary to answer the question.

 

1. Two towns are connected by railway. Can you find the distance between them?

I.The speed of the mail train is 12 km/hr more than that of an express train.

II.A mail train takes 40 minutes less than an express train to cover the distance

A.I alone sufficient while II alone not sufficient to answer

B.II alone sufficient while I alone not sufficient to answer

C.Either I or II alone sufficient to answer

D.Both I and II are not sufficient to answer

E.Both I and II are necessary to answer

Answer: Option-D

Explanation:

Let the distance between the two stations be x km.

I.              Then, speed of the mail train = (y + 12) km/hr.

II.            x/y – x/(y+12) = 40/60

Thus,even I AND II together do not give x.

So correct answer is – D

 

2. The towns A, B and C are on a straight line. Town C is between A and B. The distance from A to B is 100 km. How far is A from C?

I.The distance from A to B is 25% more than the distance from C to B.

II.The distance from A to C is 1/4 of the distance C to B.

 

A,.I alone sufficient while II alone not sufficient to answer

B.II alone sufficient while I alone not sufficient to answer

C.Either I or II alone sufficient to answer

D.Both I and II are not sufficient to answer

E.Both I and II are necessary to answer

Answer: Option-C

Explanation:

LET AC = x km. then , CB = (100-X) KM .

I.              AB=125 % OF CB

100 = 125/100 X(100-X)

100-X = 100X100 /125 =80

X =20KM

SO AC =20KM

THUS, I alone gives the answer.

   ii. AC= ¼ (100-x)

5x = 100

X = 20.

 So AC= 20 km.

Thus ii. Alone gives the answer.

So correct answer is – C

3. Two cars pass each other in opposite direction. How long would they take to be 500 km apart?

I.The sum of their speeds is 135 km/hr.

II.The difference of their speed is 25 km/hr.

 

A.I alone sufficient while II alone not sufficient to answer

B.II alone sufficient while I alone not sufficient to answer

C.Either I or II alone sufficient to answer

D.Both I and II are not sufficient to answer

E.Both I and II are necessary to answer

Answer: Option-A

Explanation:

I gives, relative speed = 135 km/hr.

SO TIME taken = 500/135 hrs.

II does not give the relative speed.

 I alone gives the answer and II is irrelevant.

Correct answer is (A).

4. How much time did X take to reach the destination?

i.The ratio between the speed of X and Y is 3 : 4

ii.Y takes 36 minutes to reach the same destination

 

A.I alone sufficient while II alone not sufficient to answer

B.II alone sufficient while I alone not sufficient to answer

C.Either I or II alone sufficient to answer

D.Both I and II are not sufficient to answer

E.Both I and II are necessary to answer

Answer: Option-E

Explanation:

Since ratio of speed of X : Y is 3 : 4, then ratio of time will be 4 : 3.

I.              If Y takes 3 min, then X takes 4 min.

II.        If Y takes 36 min, then X takes [4/3 X36] min = 48 min

Thus, I and II together give the answer.

Correct answer is (E).

 

 

 

 

 

Time and Distance - General Questions

 

Time and Distance - General Questions

1.A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

A.3.6

B.7.2

C.8.4

D.10

Answer: Option-B

Explanation:

Speed = 600/ 5 x 60 m/sec.

             = 2 m/sec.

Converting m/sec to km/hr (see important formulas section)

 =2 x 18/5 km/hr

 = 7.2 km/hr.

 

2.An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of:

A.300 kmph

B.360 kmph

C.600 kmph

D.720 kmph

Answer: Option-D

Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr.     [We can write 1  2/3 hours AS 5/3 hours]

Required speed =(1200 x 3/5)km/hr= 720 km/hr.

 

3.If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

A.50 km

B.56 km

C.70 km

D.80 km

Answer: Option-A

Explanation:

Let the actual distance travelled be x km.

Then,    x/10 = x + 20 / 14

14x = 10x + 200

4x = 200

x = 50 km.

 

4.A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

A.100 kmph

B.110 kmph

C.120 kmph

D.130 kmph

Answer: Option-C

Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150/100 X = 3/2x kmph.

75/X – 75/(3/2)X = 12510X60

75/X – 50/X = 5/24

X = (25x24 /5)

= 120 KMPH

 

5.Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

A.9

B.10

C.12

D.20

Answer: Option-B

Explanation:

Due to stoppages, it covers 9 km less.

Time taken to cover  9 km = (9/54 x 60) min = 10 min.

 

6.In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:

A.1 hour

B.2 hours

C.3 hours

D.4 hours

Answer: Option-

Explanation:

Let the duration of the flight be x hours.

Then, 600/X – 600/X+(1/2) =200

600/X – 1200/2X+1 =200

X(2X+1) =3

2 X2 +X-3 =0

(2X + 3)(X-1) =0

X = 1 hr. [neglecting the -ve value of X ]

7.A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

A.220 km

B.224 km

C.230 km

D.234 km

Answer: Option-B

Expanation

 (1/2)X/21 + (1/2)X /24 =10

X/21 +X/24 =20

15X =168X20

X = {168/20 /15} =224KM.

8.The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:

A.70 km/hr

B.75 km/hr

C.84 km/hr

D.87.5 km/hr

Answer: Option-D

Explanation:Let the speed of two trains be 7x and 8x km/hr.

Then , 8X = [400/4] =100

X = [100/8] = 12.5

SOTHAT Speed of first train  = (7x12.5) km/hr =87.5 km/hr.

9.A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

A.35.55 km/hr

B.36 km/hr

C.71.11 km/hr

D.71 km/hr

Answer: Option- C

Explanation:

Total time taken =[160/64 +160/80]hrs.= 9/2hrs.

So Average speed = [320x2/9]km/hr.

=71.11km/hr.

10.A car travelling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.

A.17 6/7 km/hr

B.25 km/hr

C.30 km/hr

D.35 km/hr

Answer: Option-D

Explanation:

Time taken = 1 hr 40 min 48 sec. = 1 hr. 40 4/5 min =1

Let  the actual speed be X km/hr.

Then , 5/7X x 126/75 = 42

X = [42x7x75 / 5x126]

=35 km/hr.

11.In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:

A.5 kmph

B.6 kmph

C.6.25 kmph

D.7.5 kmph

Answer: Option-A

Explanation:

Let Abhay's speed be x km/hr.

Then, 30/x – 30/x =3

6x =30

X = 5km/hr.

12.Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?

A.8 kmph

B.11 kmph

C.12 kmph

D.14 kmph

Answer: Option-C

Explanation:

Let the distance travelled by x km.

THEN x/10 – x/15 = 2

3x -2x =60

X = 60 km.

 Time taken to trevel 60 km at 10 km/hr. = [60/10] hrs.

So , Robert started 6 hours before 2 pm i.e. , at 8 am

So required speed = [60/5] kmph. = 12 kmph.

13.A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:

A.14 km

B.15 km

C.16 km

D.17 km

Answer: Option-c

Explanation:

Let the distance travelled on foot be x km.

Then, distance travelled on bicycle = (61 -x) km.

SO, x/4 + (61-x)/9 =9

9x +4(61-x) =9x36

5x =80

X=16km.